Five Grouped Cubes Poem by Paul Moosberg

Yes, I'm getting there now, Paul. I understand it up to the halfway point. I'll crack it eventually. Like you, I just love numbers - they are fascinating. I will keep coming back and back......... Love, Fran xx

the trick is this: 1^3=1,2^3=8,3^3=27,4^3=64,5^3=125,6^3=216,7^3=343,8^3=512,9^3=729,10^3=1000,11^3=1331 now if you take the difference of the adjacent (next to eah other) cubes then there is a pattern in that last digit of the difference between. the pattern is 79711 so it is a group of five differences that repeats and always does 79711 as the last digit of the answer. ie the differences from example above: 7,19,37,61,91,127,169,217,271,331 see last digits are 79711 repeating well the cubes that make the pattern of the last digits as 9 can caculate a later power of +6 to the lower of the 2 cubes that are adjacent in the examples at the top. but funny enough the cubes that are producing the difference with a last digit of 9 are ending in 2 or 7 since the grouping of this pattern 79711 is a group of five. then i put the counter in to show the derivations or what ever, but the difference of the difference ups by 150 evey 5 cubes so this gave me a way to calculate what the 2nd or the 3rd in the next group by flopping the opposing to the other side of the equal sign with some different math to them. but the basis is that i can calculate the numbers cubed if the numbers being cubed end in 2 or 7. it's kinda funny that it works cause it is really wierd to see it in my head like spinning spirals of math and color.

Hell, it's a long time since I had to use algebra (and a long time since I worked in the electronics business) . I tried to understand this but just couldn't. My mind is all scrambled up now............but thanks for a poem that really got me thinking. Love, Fran xx